PowerShell - How to use && type statement [duplicate]

Question

Using the command below, I am able to get the value of a group policy setting:

secedit.exe /export /cfg C:\test\secedit.txt && type C:\test\secedit.txt | findstr "SeEnableDelegationPrivilege"

I need to be able to use the same command on PowerShell and I am having issues converting the && statement to work on PowerShell. I tried using this format () -and (), however, that has not worked, does anyone know a way of getting the && statement to work on PS?

In short: Only PowerShell v7+ supports && and ||, the pipeline-chaining operators - see this answer. In earlier versions, notably in Windows PowerShell, you can emulate a && b with a; if ($?) { b } and a || b with a; if (-not $?) { b } - see this answer — mklement0
– mklement0, Commented Jun 11, 2021 at 15:50

Santiago Squarzon · Accepted Answer · 2021-06-11 15:54:06Z

1

If you want to emulate what that command is doing in PowerShell just change the && for a ;:

secedit.exe /export /cfg C:\test\secedit.txt; type C:\test\secedit.txt | findstr "SeEnableDelegationPrivilege"

I would add 1>$null after the first command to avoid the output of The task has completed successfully.....

Edit

I understand ; and && or || are not the same thing in PS 5.1 and below, but is the closest thing I can imagine to emulate what OP is doing.

Other thing he could attempt is:

secedit.exe /export /cfg C:\test\secedit.txt;if($?){type C:\test\secedit.txt | findstr "SeEnableDelegationPrivilege"}

I would link this helpful answer which explains it better than I do.

edited Jun 11, 2021 at 15:54

answered Jun 11, 2021 at 15:37

Santiago Squarzon

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4 Comments

vonPryz Over a year ago

Powershell supports nowadays pipeline chaining operators && and ||. Those are not the same as a semicolon?

Santiago Squarzon Over a year ago

@vonPryz Yeah I know PS Core supports && and || however OP clearly is not using PS Core or hes command would have worked.

Help Over a year ago

Thank you guys!! The recommended parameters work well on my version of PS.

Santiago Squarzon Over a year ago

@Help you probably already have but if not, have a read at the answer I posted in my edit. It explains the PS behaviour better than I do.

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