PHP Switch statement error

Question

 <?php
 include 'db.php';
 $mail=$_SESSION['session_u_e_mail'];
if(!isset($_GET['edit']))
{
$_GET['edit']=0;
}
switch($_GET['edit'])
{
 case 1: echo "Value";
         break;

 case 2: echo "Value";
         break;

 default: echo "Value";
         break;

 }

I m facing problem that the values in every case is echoed twice.

Are you certain the problem comes from those lines and not something after that? — Mat
– Mat, Commented Jul 23, 2011 at 12:37
@user855360: No, it doesn't. Make a testcase that demonstrates the issue. — Lightness Races in Orbit
– Lightness Races in Orbit, Commented Jul 23, 2011 at 12:40

Tarik · Accepted Answer · 2011-07-23 12:40:07Z

2

I've just grabbed the

if(!isset($_GET['edit']))
{
$_GET['edit']=0;
}
switch($_GET['edit'])
{
 case 1: echo "Value";
         break;

 case 2: echo "Value";
         break;

 default: echo "Value";
         break;

 }

this portion and pasted onto codepad and it works fine.

Here is the working version: http://codepad.org/P8bhL5vl

It outputs just "Value".

answered Jul 23, 2011 at 12:40

Tarik

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1 Comment

Tarik Over a year ago

Probably your code going bad in your db.php file. Check that out and you will find the problem.

phihag · Accepted Answer · 2011-07-23 12:38:17Z

0

There is nothing in this code that would even output your default value. No matter the input, this outputs Value. Look in db.php or the files included by it for debugging echoes.

answered Jul 23, 2011 at 12:38

phihag

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