Is there a simple way to count the total number of pdf files in a folder that contains a number of other folders among which some contain multiple level subfolders and others just pdf files?
This answer provides a very good solution to count number of files in each folder on the first subfolder level but not further down to individual pdf files.
Provided your pdfs end in the expected file extension, the solution is trivial:
import os
my_folder = "./" # your path here
count = 0
for root, dirs, files in os.walk(my_folder):
count += len([fn for fn in files if fn.endswith(".pdf")])
print(count)
It is a separate question if you want to determine the filetype by the contents directly; that is a harder problem.
help(os.walk) and scroll to the example at the bottom. The code should look familiar :DIs this what you want?
import os
count=0
def new_folder(path,arrs):
global count
for arr in arrs:
if os.path.isdir(path+"\\"+arr): #=== Joins the path with the name and check if it is a folder
try:
a1=os.listdir(path+"\\"+arr)
new_folder(path+"\\"+arr,a1) #=== Pass that as a function and iterate over it.
except PermissionError: #=== Permission denied
pass
else:
if arr.endswith(".pdf"): #=== If it ends with a .pdf extension
print(path+"\\"+arr) #=== Print file path
count+=1 #=== Add 1 to count
return count
path="C:\\Users\\91996"
arrss=os.listdir(path) #== List all files and directories
print("PDF Files Found: ",new_folder(path,arrss))