Include php page with variable

Question

I know that it is possible to include php file with variables. It looks like this sample.

include 'http://www.example.com/file.php?foo=1&bar=2';

How to include php file on local file system (instead of url) with variables? Smth like that.

include 'file.php?foo=1&bar=2';

Is it possible?

UPDATE I wanna get variable from index page and include the file with exact variable from local system to content div. smth like that

<?php
$foo=$_GET['foo'];
$bar=$_GET['bar'];

?>
<body>
<div id="main">
<div id="content">
<?php
include 'file.php?foo='.$foo.'&bar='.$bar;
?>
</div>
</div>
</body>

for local files it's impossible. Set your variables before including the other files. As you can get GET variables by $_GET so you can set them also with $_GET — rabudde
– rabudde, Commented Jul 25, 2011 at 5:04

Shakti Singh · Accepted Answer · 2011-07-25 05:04:27Z

6

Variables are simply available in the file to be included. There is no file scope for variables.

so if you do this

$foo=1; $bar=2;
include 'file.php';

$foo and $bar will be available in the file.php.

The variables declared above this included statement will be available in the file.php file.

answered Jul 25, 2011 at 5:04

Shakti Singh

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1 Comment

rabudde Over a year ago

this wouldn't work. he wants to pass the variables explicit. so you have to assume, that in file.php he's setting the variables via $_GET

cantlin · Accepted Answer · 2011-07-25 05:05:11Z

1

Included files have access to whatever variables are defined in the scope they were called in. So, anything you define before the include will be set in the included file.

# foo.php

$foo = 'bar';
include 'bar.php';

# bar.php

echo $foo;

When foo.php is run, the output will be 'bar'.

answered Jul 25, 2011 at 5:05

cantlin

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Comments

David Wolever · Accepted Answer · 2011-07-25 05:06:13Z

1

What do you expect the variables to do? Maybe something like this:

<?
$_GET["foo"] = "1";
$_GET["bar"] = "2";
include "file.php";
?>

answered Jul 25, 2011 at 5:06

David Wolever

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Comments

bozdoz · Accepted Answer · 2011-07-25 05:15:18Z

1

I think you have it reversed: should be $foo = $_GET['foo'] etc.

answered Jul 25, 2011 at 5:15

bozdoz

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