Unexpected output in Python while executing simple loop

Question

I have this rather simple loop

cities = ['Merano', 'Madrid', 'New York', 'Bangkok']
countries = ['Italy', 'Spain', 'USA']

for index, city in enumerate(cities):
    print('This is index:', index)
    print('This is city:', city)
    print('The length of the list \'cities\' is: ', len(cities))
    print(print('The length of the list \'countries\' is: ', len(countries)))
    print(countries[index])
    print(5 * '#')

I expect it to break. However, what I did not expect is this output.

This is index: 0
This is city: Merano
The length of the list 'cities' is:  4
The length of the list 'countries' is:  3
None
Italy
#####
This is index: 1
This is city: Madrid
The length of the list 'cities' is:  4
The length of the list 'countries' is:  3
None
Spain
....

Where is the none coming from? I do not print this, nor do I execute something where I'd expect this to be printed...

icp · Accepted Answer · 2021-06-30 11:18:50Z

4

you used print(print()) in print(print('The length of the list \'countries\' is: ', len(countries))) use

print('The length of the list \'countries\' is: ', len(countries))`

answered Jun 30, 2021 at 11:18

icp

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AJITH · Accepted Answer · 2021-06-30 11:06:08Z

2

Because you have 2 print commands

print(print('The length of the list \'countries\' is: ', len(countries)))

answered Jun 30, 2021 at 11:06

AJITH

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four-eyes Over a year ago

Oh wow... I should have looked closer ;) Thanks!

aj95 · Accepted Answer · 2021-06-30 11:33:08Z

1

print(print('The length of the list \'countries\' is: ', len(countries)))

in the above line you are printing print functions output.

If you look at function Def it doesn't have a return type so you are getting None from the inner print() statement.

Also a remark- fix the index check for index > len(countries)

edited Jun 30, 2021 at 11:33

answered Jun 30, 2021 at 11:16

aj95

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