Execute selenium click with ID based on different classes in Java

Question

I have two selenium elements where i need to click. But these elements are with a different id.

findElement(By.id(ID_1)).click();

findElement(By.id(ID_2)).click();

findElement(By.id(ID_1)).click() should be clicked if the Class_1 is executed, if Class_2 is called, then findElement(By.id(ID_2)).click() should be clicked.

I am trying to avoid duplicate code because these above 2 find elements are inside one method which is called Class_1 and Class_2.

I tried something like this but it didn't solve my issue

  if (Class_1.class)
        {
            findElement(By.id(ID_1)).click();
        }
    
  else if (Class_2.class)
        {
            findElement(By.id(ID_2)).click();
        }

I am getting "Type mismatch: cannot convert from Class<Class_1> to boolean". I mean I am trying to do like this. If this is class_1, then run this, else run else if part.

Thanks for any guidance in advance.

I did not get it, why do you want to differentiate based on class ? why not in a single class ? — cruisepandey
– cruisepandey, Commented Jul 2, 2021 at 10:51
@cruisepandey because these two classes refers to different IPs addresses to perform some tasks. and both classes access to this method. If i create two methods, then issue is solved but code will be duplicated. — Rio
– Rio, Commented Jul 2, 2021 at 10:53

pburgr · Accepted Answer · 2021-07-02 11:02:42Z

1

You schouldn't separate your test into two (or more) different classes. Instead use one class and parametrize your method:

public void myTestMethod(String ipAdress) {
    if (ipAdress.equals("FOO_IP")) {
        findElement(By.id("FOO_ID")).click();
    }
    else if (ipAdress.equals("BAR_IP")) {
        findElement(By.id("BAR_ID")).click();
    }
    else {
        // code for uknown ip adress
    }
}

and simply call the method with desired argument:

myTestMethod("FOO_IP");
myTestMethod("BAR_IP");

answered Jul 2, 2021 at 11:02

pburgr

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