Take numbers out of an array Ruby

Question

New to programming and Ruby. I'm working with the iStock API and need to send a fileID to request information about files I have.

Example files I have that I need get to request info on iStock:

["iStock_000001053628Small.jpg", "iStock_000002270952Big_Web.mov", "ist2_7034929-blurred-commuter.jpg", iStock_000000042199Medium.jpg]

Working in irb, the code I send to iStock's API:

require 'xmlrpc'
parameters = {:apiKey=>"#", :fileID=>"1053628"}
server = XMLRPC::Client.new2( "http://api.istockphoto.com/webservices/xmlrpc")
server.call("istockphoto.image.getInfo", parameters)

Challenge: I need to extract the fileID numbers out of the array. This means I have to take all the zeros off the front of the file number. However, the file numbers differ in length and the number of zeros in the front differs for each image.

istock.each do |x|
  result = ' '
  x.scan(/\d+/) do |y|
    if y.to_i > 4
      result << y
    end
    puts result
  end
end

000001053628
000002270952
7034929
000000042199

I'm not sure how to approach this problem because if I set up rules for the sets of 0's, there might be a time when the actual fileID also has these in it.

Kamiel Wanrooij · Accepted Answer · 2011-07-25 22:32:06Z

2

I am not sure about what different filename formats you have to support, but something like this works for me:

$ irb
irb(main):001:0> test_data = ["iStock_*000001053628*Small.jpg", "iStock_000002270952BigWeb.mov", "ist2_7034929-blurred-commuter.jpg", "iStock_*000000042199*Medium.jpg"]
=> ["iStock_*000001053628*Small.jpg", "iStock_000002270952Big Web.mov", "ist2_7034929blurred-commuter.jpg", "iStock_*000000042199*Medium.jpg"]
irb(main):002:0> test_data.map do |d|
irb(main):003:1*   d.scan(/\d{4,}/).first.gsub(/^0+/,'')
irb(main):004:1> end
=> ["1053628", "2270952", "7034929", "42199"]
irb(main):005:0>

answered Jul 25, 2011 at 22:32

Kamiel Wanrooij

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1 Comment

Lars Haugseth Over a year ago

Instead of gsub, a sub would have been sufficient here. But you do without a sub as well: d.scan(/[1-9]\d{3,}/).first, or simply d.scan(/\d{4,}/).first.to_i to get the raw numbers.

Dan Tao · Accepted Answer · 2011-07-25 22:35:08Z

0

I'm not sure what this line is about:

if y.to_i > 4

But it sounds like you just want to remove leading zeros, correct?

In that case, just try this:

# Parse the string as an integer, then re-format as a string.
result << y.to_i.to_s

This will populate your result array with strings whose leading zeros have effectively been removed.

answered Jul 25, 2011 at 22:35

Dan Tao

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