RegExp equivalent of an actual regex string

Question

Please what is the RegExp equivalent of /^STRINGA/i in javascript? For example, new RegExp('country', 'i') will give /country/i, but i do not know how to achieve the aforementioned regex.

My current workaround is to cacatenate ^ to the string before passing it to the regex, but there should be a proper way of going about it — Valiant
– Valiant, Commented Jul 9, 2021 at 19:07

Robiul · Accepted Answer · 2021-07-09 20:18:30Z

1

as first I want to say in javascript we can write regex 2 ways

literal likes /pattern/modifiers using slashes /
constructor likes new RegExp("pattern", "modifiers") using constructor function

regex has several special characters if a pattern has a special character you can scaping with the use of backslash \ this backslash also I used inside of StackOverflow editor 2-time then it showed it scaping any special character.

const pattern = /\/\^STRINGA\/i/;
const string = '/^STRINGA/i';
console.log(string.match(pattern));

Note: / / first and last slashes used to making the regex pattern, and all \ backslash used for scaping the special character

answered Jul 9, 2021 at 20:18

Robiul

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Titus · Accepted Answer · 2021-07-09 19:17:19Z

0

You just need to escape special characters. For example, using the RegExp constructor, you can do this:

const ex = new RegExp('\\/\\^STRINGA\\/i');
console.log('/^STRINGA/i'.match(ex));

And using an expression, you can do this:

const ex = /\/\^STRINGA\/i/;
console.log('/^STRINGA/i'.match(ex));

answered Jul 9, 2021 at 19:17

Titus

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