replace relative path with a regular expression on asyncronously loaded css

Question

I'm asyncronously loading a css.

@font-face{
    src: url('fonts/le-havre-1_300_normal-webfont.eot');
    src: url('fonts/le-havre-1_300_normal-webfont.eot?#iefix') format('embedded-opentype'),
    url('fonts/le-havre-1_300_normal-webfont.woff') format('woff'),
    url('fonts/le-havre-1_300_normal-webfont.ttf') format('truetype'),
    url('fonts/le-havre-1_300_normal-webfont.svg#LeHavreLight') format('svg');
}

I have to replace the path dynamically, for example:

url(' -> url('http://www.site.com/skin/light/

I wrote this regular expression but it seems to replace only the first value.

var newCss = cssText.replace(/url\(\'(.+)\'\)/g, function(a,b){
    return 'url(\''+'http://www.site.com/skin/light/' + b + '\')';
});

How can I replace all the url attributes?

perfect! but why do you write the answer in a comment?

Luke
– Luke

2011-07-26 18:27:23 +00:00
Commented Jul 26, 2011 at 18:27 — Luke
– Luke, Commented Jul 26, 2011 at 18:27
couldn't remember if multi-line was disabled in this case.

Dor
– Dor

2011-07-26 18:36:44 +00:00
Commented Jul 26, 2011 at 18:36 — Dor
– Dor, Commented Jul 26, 2011 at 18:36

gpojd · Accepted Answer · 2011-07-26 18:25:12Z

1

Try the /m modifier too. Since the string has multiple lines, it probably needs it.

/url\('([^)]+)'\)/gm

answered Jul 26, 2011 at 18:25

gpojd

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Dor · Accepted Answer · 2011-07-26 18:34:08Z

0

The regexp/url\(\'(.+?)\'\)/g solves the problem, because of the un-greediness of the expression .+?, in contrast to the greedy expression .+ that matches to the entire following string
(if multi-line enabled):

url('fonts/le-havre-1_300_normal-webfont.eot');
src: url('fonts/le-havre-1_300_normal-webfont.eot?#iefix') format('embedded-opentype'),
url('fonts/le-havre-1_300_normal-webfont.woff') format('woff'),
url('fonts/le-havre-1_300_normal-webfont.ttf') format('truetype'),
url('fonts/le-havre-1_300_normal-webfont.svg#LeHavreLight') format('svg')

See the "U (PCRE_UNGREEDY)" modifier: Pattern Modifiers @ php.net

answered Jul 26, 2011 at 18:34

Dor

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