return a string inside a function

Question

Task Instructions
In this activity, you will define a variable within a JavaScript function. You'll learn more about functions later. For now, we'll focus on variables.

To accomplish this task, you need to do the following:

Open the Variables-01 folder and add code to the variables01.js file to do the following:

Create a variable called myFriend using one of the variable declarations described above.

Set the variable you created to contain your friend's name.

Inside the greetings function, return the string: "Greetings [your-friend's-name]."

I have no idea what I am missing in this code but it still comes up as wrong.

/*Instructions
 - Greet your friend by printing a message to the console.
*/
function greetings(greetings ,{myFriend}) {
  var myFriend = 'Mike';
  `greetings ${myFriend}`;
  console.log(myFriend);
  

}

//leave this line unchanged to console log the results
console.log('results: ', greetings());

//don't change this line
if (typeof module !== 'undefined') {
  module.exports = greetings;
}

The instructions tell you exactly what you need to do: Inside the greetings function, return the string: — Barmar
– Barmar, Commented Jul 19, 2021 at 17:13
You could also just make it function greetings(){ as you are not using the arguments. — The fourth bird
– The fourth bird, Commented Jul 19, 2021 at 17:15

ᴓᴓᴓ · Accepted Answer · 2021-07-19 17:33:37Z

1

You need a return statement:

https://www.w3schools.com/jsref/jsref_return.asp

ex.

/*Instructions
 - Greet your friend by printing a message to the console.
*/
function greetings() {
  var myFriend = 'Mike';
  console.log(myFriend);
  return `greetings ${myFriend}`;
}

//leave this line unchanged to console log the results
console.log('results: ', greetings());

//don't change this line
if (typeof module !== 'undefined') {
  module.exports = greetings;
}

edited Jul 19, 2021 at 17:33

answered Jul 19, 2021 at 17:12

ᴓᴓᴓ

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3 Comments

ᴓᴓᴓ Over a year ago

If it's automarking, make sure it matches exactly: capitalize "greetings" and add a period at the end.

HackAttack101 Over a year ago

It says 'TypeError: Cannot read property 'myFriend' of undefined'

ᴓᴓᴓ Over a year ago

See my edit. You don't need arguments on the greetings() function. The error occurs because of the {myFriend} you had as an argument for greetings()

The fourth bird · Accepted Answer · 2021-07-19 20:31:01Z

0

A few issues with the code:

The function greetings does not return a value
You use console.log multiple times, but you could log the return value of the function a single time
The function arguments greetings(greetings ,{myFriend}) are not used

If you want to write a function without an explicit return statement, you could shorten the code using a single parameter myFriend with an arrow function.

const greetings = myFriend => `greetings ${myFriend}`;
console.log('results: ', greetings("Mike"));

if (typeof module !== 'undefined') {
  module.exports = greetings;
}

const greetings = myFriend => `greetings ${myFriend}`;
console.log('results: ', greetings("Mike"));

answered Jul 19, 2021 at 20:31

The fourth bird

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