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Hello (beginner here),

I am trying to write a script that prints the sum of every even numbers in the range [0; 100].

However, I am getting a "TypeError: 'int' object is not iterable".

This is my code:

for i in range(0, 101):
    total = 0
    if i % 2 == 0:
        total = sum(i)
        print(total)

My error message:

Traceback (most recent call last): File "", line 4, in TypeError: 'int' object is not iterable

I've searched this website and Google to understand what I'm doing wrong, but I cant seem to grasp an answer to my specific code.

Any help would be greatly appreciated.

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  • 1
    sum computes the sum of its argument, e.g. sum([1, 2, 3]) == 6. Passing it a single integer is not sensible. Did you mean total += i instead? Commented Jul 19, 2021 at 17:20
  • Note that you still have another issue, in that total is defined at the wrong place... Commented Jul 19, 2021 at 17:23
  • 1
    If you want to do this concisely, just doing total = sum(range(0, 100, 2)) is enough. Commented Jul 19, 2021 at 17:24
  • Hello @MisterMiyagi (awesome name) YES !!!! You are correct on all those comments. It was a good learning experience for me. Thank you :) Commented Jul 20, 2021 at 14:05

3 Answers 3

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The problem is with the sum function it is not used in that manner. If you give 1 argument then it should be a list then you can use .append() function but in your use-case you can simply use + i.e., addition.

total = 0
for i in range(0, 101):
    if i % 2 == 0:
        total += i
        print(total)
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The sum() function can only sum up an iterable (list, dict, etc.). In your loop, your variable i is seen as a solid number, not a list. If you want to sum up every even number, you need to add i to a list:

list1 = []
for i in range(0, 101):
    if i % 2 == 0:
         list1.append(i)
         total = sum(list1)
         print(total)

Here is a better version, if you do not want the output after every single addition:

print(sum([i for i in range(0,101, 2)]))
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6 Comments

This computes the sum of all prefixes of the list of even integers, and expensively as well. You compute 0, then 0+2, then 0 + 2 + 4, etc, rather than just keeping a running total.
In general, I agree with you. In practice is the execution speed not noticeable for his/her use case. I thought he/she wants to use the sum() function and this is the easiest way to show how it works
The question is pretty clear: the OP wants the sum of the even integers between 0 and 100. sum lets you do that without an explicit loop. There's no reason to suggest that code like this is acceptable.
I updated my answer, even if I disagree. OP wanted to print out the sum after every single addition not once.
Hi Dakopen - this is what I wanted and you showed me a way to do it with printouts of a running total and a grand total. Thank you for helping me. I'm new to Python, programming and StackOverflow :)
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the answer to your question using sum function can simply be

for i in range(0, 101, 2):
    total = 0
    total = sum(i, total)
    print(total)

Learn more about Python loops here!
Learn Python fundamentals here!

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