Typedef pointer to an array of another typedef

Question

I will like to declare a typedef, something like this:

for e.g.:

Typedef 1:

typedef struct
{
    int a;
}structA_t1;

Typedef 2:

typedef ptrstructA  structA_t1 (*Temp)[]  ;

Is this second typedef correct ? Do i really need this Temp name here ? Please suggest, thanks

Wouldn't it be typedef structA_t1 (*ptrstruct)[]; or somethin — JAB
– JAB, Commented Jul 27, 2011 at 17:56
Why do you want to make a typedef like that? It's commonly considered poor form to create typedefs that hide that fact that something's a pointer. — Carl Norum
– Carl Norum, Commented Jul 27, 2011 at 18:19

Yochai Timmer · Accepted Answer · 2011-07-27 18:02:23Z

7

The name of the newly defined type comes in the end:

typedef structA_t1 **ptrstructA;

or:

typedef structA_t1 (*ptrstructA)[];

answered Jul 27, 2011 at 18:02

Yochai Timmer

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1 Comment

More specifically, it replaces the variable name that would be there if it weren't a typedef.