Sort based on datetime object inside of the list

Question

I have a list of "snapshots" which look like this

{ description: "sdoiajosdi", "startDate": datetime.datetime(2021, 7, 16, 22, 47, 50, 609000, tzinfo=tzlocal()), Tags: [ {'sdklapsijd':'asdjiosoid'}], ownerId: "osjdaiosjd" }

These are stored in a python list. Is there a way I can sort ascending or descending based on the 'startDate' property for each item in the list? So if I have 100 snapshot objects, with differing datetime.datetime properties, can I use this as the 'sorting key?' How can I do this?

Of course. Just provide an appropriate key= argument to the sort() method. — Barmar
– Barmar, Commented Jul 28, 2021 at 20:48
Does this answer your question? How do I sort a list of dictionaries by a value of the dictionary? — wjandrea
– wjandrea, Commented Jul 28, 2021 at 20:51

wjandrea · Accepted Answer · 2021-07-28 20:51:29Z

1

As datetime objects are comparable, you should just be able to sort the list with:

sorted(snapshots, key=lambda x: x["startDate"])

edited Jul 28, 2021 at 20:51

wjandrea

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answered Jul 28, 2021 at 20:48

sj95126

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1 Comment

Ryan Glenn Over a year ago

That looks like what I was just reading! Thanks :)

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