I am trying to generate 5 unique random numbers and I have written a for loop for it:
for i in range(5):
print("enter a no")
x = int(input())
if x not in a:
a.append(x)
If x is not in a, only then i should be incremented. I can do this with while loop but want to know if we can do this with a for loop.
You can do this by converting a range into list. Please follow the given example code.
a = list()
n = 2
myrange = list(range(n)) # converting your range into list
for i in myrange:
print("enter a no")
x = int(input())
if x not in a:
a.append(x)
else :
# add current i again in the rangelist at starting position
myrange.insert(0,i)
You can't change how many times for i in range() loop runs. Changing i in the loop has no effect on the range() object.
You can use a nested loop that keeps asking until it gets a number that's not found.
for _ in range(5):
while True:
print("enter a no")
x = int(input())
if x not in a:
a.append(x)
break
Here are some approaches:
Option 1 :
Using an infinite value in the range function :
def to_infinity():
index = 0
while True:
yield index
index += 1
for i in to_infinity():
print("enter a no")
x = int(input())
if len(a) > 5:
break
if x not in a:
a.append(x)
Option 2 :
Using itertools.count:
import itertools
for i in itertools.count(start=1):
print("enter a no")
x = int(input())
if len(a) > 5:
break
if x not in a:
a.append(x)
append instead?
forloop should terminate after finitely many iterations.