Is there a way to check within an array nested in a dict?

Question

I am not even sure if this is possible as I am new to python. Essentially I want to construct a dict for lookup purposes - this is my first stab at a data structure.

lookup = {
    1000000: {
        "Name":"Neutral grassland",
        "values":[6150166, 1000000, 1000283, 1000516, 1000524, 1000525, 1000526, 
                  1300000, 1300016, 1300017, 1300522, 1300527, 1310000, 1320000]
    }
}

I would like a method, a little like get() but where I can return the whole object of 100000 when a number is found within the values array.

Is this possible? Bonkers?

if my_value in lookup[1000000]["values"]: do_something()

MattDMo
– MattDMo

2021-08-03 12:15:22 +00:00
Commented Aug 3, 2021 at 12:15 — MattDMo
– MattDMo, Commented Aug 3, 2021 at 12:15

MorganS42 · Accepted Answer · 2021-08-03 12:20:16Z

1

Is this what you were thinking?

def search(num, lookup):
    for inner in lookup:
        if num in inner["values"]:
            return inner

lookup = {
    1000000: {
        "Name":"Neutral grassland",
        "values":[6150166, 1000000, 1000283, 1000516, 1000524, 1000525, 1000526, 1300000, 1300016, 1300017, 1300522, 1300527, 1310000, 1320000]
    }
}
n = 6150166
search(n, lookup)

edited Aug 3, 2021 at 12:20

answered Aug 3, 2021 at 12:17

MorganS42

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1 Comment

MattDMo Over a year ago

Don't use dict, list, str, etc. as variable names - you're shadowing the builtins.

user16519472 · Accepted Answer · 2021-08-03 12:23:02Z

0

Try this:

def get(v):
    if v in lookup[1000000]["values"]:
        return lookup[1000000]

It's pretty specific to the lookup dictionary, but it can be modified to support others.

answered Aug 3, 2021 at 12:23

user16519472

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