Suppose I have the following DataFrame:
A B C D E F Cost
0 1 1 0 0 0 10
0 0 1 0 1 0 3
1 0 0 0 0 1 5
0 1 0 1 0 0 7
I want to construct a new DataFrame based on the values above.
Specifically, if value==1 then combine their columns into one and assign value for the new column from Cost column above.
So the expected output would be something like:
BC CE AF BD
10 3 5 7
How can I achieve such thing?
We can try the dot of the the binary columns with the column names to get the key string based on 1s and 0s, then add the Cost Column back:
cols = df.columns.difference(['Cost'])
new_df = df[cols].dot(cols).to_frame(name='key')
new_df['Cost'] = df['Cost']
new_df:
key Cost
0 BC 10
1 CE 3
2 AF 5
3 BD 7
The DataFrame can be transposed if needed:
cols = df.columns.difference(['Cost'])
new_df = df[cols].dot(cols).to_frame(name='key')
new_df['Cost'] = df['Cost']
new_df = new_df.set_index('key').T.rename_axis(columns=None)
new_df:
BC CE AF BD
Cost 10 3 5 7
DataFrame and imports:
import pandas as pd
df = pd.DataFrame({
"A": [0, 0, 1, 0],
"B": [1, 0, 0, 1],
"C": [1, 1, 0, 0],
"D": [0, 0, 0, 1],
"E": [0, 1, 0, 0],
"F": [0, 0, 1, 0],
"Cost": [10, 3, 5, 7],
})
You don't need a loop to do it. With datar, you can achieve it with dplyr-like syntax:
>>> from datar.all import *
>>>
>>> # Create the df
>>> df = tribble(
... f.A, f.B, f.C, f.D, f.E, f.F, f.Cost,
... 0, 1, 1, 0, 0, 0, 10,
... 0, 0, 1, 0, 1, 0, 3,
... 1, 0, 0, 0, 0, 1, 5,
... 0, 1, 0, 1, 0, 0, 7,
... )
>>> df
A B C D E F Cost
<int64> <int64> <int64> <int64> <int64> <int64> <int64>
0 0 1 1 0 0 0 10
1 0 0 1 0 1 0 3
2 1 0 0 0 0 1 5
3 0 1 0 1 0 0 7
>>> # replace value with column names
>>> df = df >> mutate(across(f[1:6], lambda x: if_else(x, x.name, "")))
>>> df
A B C D E F Cost
<object> <object> <object> <object> <object> <object> <int64>
0 B C 10
1 C E 3
2 A F 5
3 B D 7
>>> # unite the columns
>>> df = df >> unite('col', f[1:6], sep="")
>>> df
col Cost
<object> <int64>
0 BC 10
1 CE 3
2 AF 5
3 BD 7
>>> # reshape the result
>>> df >> column_to_rownames(f.col) >> t()
BC CE AF BD
<int64> <int64> <int64> <int64>
Cost 10 3 5 7
Disclaimer: I am the author of the datar package.
datar.. Thanks!Here is how I will proceed:
data = {
"A": [0, 0, 1, 0],
"B": [1, 0, 0, 1],
"C": [1, 1, 0, 0],
"D": [0, 0, 0, 1],
"E": [0, 1, 0, 0],
"F": [0, 0, 1, 0],
"Cost": [10, 3, 5, 7],
}
df = pd.DataFrame(data)
def make_df(row):
row = row.to_dict()
return "".join([k for k, v in row.items() if v if k!="Cost"])
df_ind = df.apply(make_df, axis=1)
pd.DataFrame(df.Cost.values, index=df_ind.values).T
This will give you:
BC CE AF BD
10 3 5 7
Not as nice as previous answers, but straightforward & step-by-step:
outp_dict = {}
for index, row in df.iterrows():
new_col = ""
col_nr = 0
for value in row:
if value and row.index[col_nr] is not "Cost":
new_col += str(row.index[col_nr])
col_nr += 1
outp_dict[new_col] = row[-1]
outp_df = pd.DataFrame(outp_dict, index = [0])
