Python newbie here. Let's say we have an array which contains 10 random integers. I want to check if each value of the integers is 0<= x <= 9. So for example somehow like this:
if 0 <= n[:11] <=9:
print('correct')
'n[:10]' is treated like a list so I can't compare it with 0 and 9. Is there an elegant way to check the range of items in that array?
I don't want to code something like:
if 0 <= n[0] and n[1] and ... n[9] <=9:
thanks for your help
Check this out:
This returns True if and only if ALL of the numbers in the list n are at least 0 and at most 9, (in range(0, 10))
all(i in range(0, 10) for i in n)
if 0 <= min(n) <= max(n) <= 9:
Could use and instead of <= in the middle, not sure which I like better.
What you want is the check the equality for every elements:
all(0 <= item <= 9 for item in n)
If you first sort the list you only have to check the first and last value, like this:
sorted_n = sorted(n)
if sorted_n[0] > 0 and sorted_n[-1] < 10: # returns True or False for whole list
all(0 <= i <= 9 for i in n[:11])…