How to remove dictionaries from list with keys matching another list [duplicate]

Question

idlist = ['101', '102']

myd = [
    {'id':'101', 'role': 'tester'},
    {'id':'102', 'role': 'tester'},
    {'id':'103', 'role': 'tester'}
]

I have idlist
I need to check if a dictionary with the id is present in myd
I need to remove the items with matching id

Expected output:

101 and 102 are deleted

[{'id':'103', 'role': 'tester'}]

Code is below

for ids in idlist:
    for each in myd.items():
        if ids == each['id']
             del each

Do I need to do 2 for loop function to resolve this?

myd is a list so myd.items() won't do anything. You need to break down your problem into steps instead of trying to tackle everything at the same time. — Peter
– Peter, Commented Aug 26, 2021 at 15:14

user2390182 · Accepted Answer · 2021-08-26 15:14:49Z

3

You can use a simple comprehension:

s = set(idlist)  # better membership test than list

myd[:] = [d for d in myd if d['id'] not in s]

It is usually better to build a list from scratch than to repeatedly remove elements. The slice assignment myd[:] = ... just makes sure this is a mutation on the existing list object as removing elements would be.

answered Aug 26, 2021 at 15:14

user2390182

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RMRiver · Accepted Answer · 2021-08-26 15:19:37Z

2

A single liner:

myd = [x for x in myd if x['id'] not in idlist]

Esentially creates a new list with the values that are not in idlist. You can assign this to myd if you like to overwrite it.

NOTE: This is not deleting from the list but rather replacing the list.

answered Aug 26, 2021 at 15:19

RMRiver

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