How to convert ASCII values that are substring inside a string to its character

Question

How to convert ASCII values that are substring inside a string to its character? For example:

If I give input as

H105 68u100e33 65r101 89o117?

I need output as

Hi Dude! How Are You?

In the above input after every alphabet or spaces there is an ASCII value.

char[] a = new char[2];
char t;
String temp,output="";

for(int i=0;i<str.length()-1;i++){
    a[0]=str.charAt(i);
    a[1]=str.charAt(i+1);
    if(Character.isDigit(a[0])){
        if(Character.isDigit(a[1])){
            String con=String.valueOf(a[0])+String.valueOf(a[1]);
            int n=Integer.parseInt(con);
            output=output+(char)n;
        }else{
            //nothing
        }
    }else{
        output=output+a[0];
    }
}

System.out.println("output : "+output);

I have tried something like this, and it fails at 3 digit ASCII values and also sometimes I face array index outofbound error due to charAt(i+1) statements.

How to change that ASCII values to its char and form a sentence?

Will your final sentence always contain alphabets?

Anuj
– Anuj

2021-08-27 05:53:30 +00:00
Commented Aug 27, 2021 at 5:53 — Anuj
– Anuj, Commented Aug 27, 2021 at 5:53

Melron · Accepted Answer · 2021-08-27 08:01:17Z

1

You have to create your algorithm based on the phrase "Get all the digits first, and then for each one, replace it with its ASCII value"

So,

public static void main(String[] args)
{
    String input = "H105 68u100e33 65r101 89o117?";
    
    // Get all the digits by replacing the non-digits with space
    // And then split the string with space char to get them as array
    final String[] digits = input.replaceAll("\\D+"," ").trim().split(" ");
    
    // For each one, replace the main input with the ascii value
    for (final String digit : digits)
        input = input.replaceAll(digit, Character.toString(Integer.parseInt(digit)));
    
    System.out.println(input);
}

edited Aug 27, 2021 at 8:01

answered Aug 27, 2021 at 6:29

Melron

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Comments

score 1 · Accepted Answer · 2021-08-27 08:39:45Z

1

Try this.

static final Pattern NUM = Pattern.compile("\\d+");

public static void main(String[] args) {
    String input = "H105 68u100e33 65r101 89o117?";
    String output = NUM.matcher(input)
        .replaceAll(m -> Character.toString(Integer.parseInt(m.group())));
    System.out.println(output);
}

output:

Hi Dude! Are You?

NUM is a pattern that matches one or more digits.
NUM.matcher(input).replaceAll() replaces all characters that match this pattern in input.
m-> Character.toString(Integer.parseInt(m.group())) converts the matched numeric string to an integer and then converts to the string corresponding to that character code.

edited Aug 27, 2021 at 8:39

answered Aug 27, 2021 at 7:16

user4910279

2 Comments

Joop Eggen Over a year ago

Please explain the regex pattern and the answer is perfect.

user4910279 Over a year ago

@JoopEggen I have added a description for this code.

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