Javascript display all elements of array except for the specified index

You can use .filter() to filter out elements. So, in this case filter out all the elements of the array which is not blue.

var color = ["red", "green", "blue", "yellow"];
console.log(color.filter(col => col !== "blue"));

1) You can use a filter here

var color = ["red", "green", "blue", "yellow"];
const result = color.filter((c) => c !== "blue");
console.log(result);

2) Although you can also use splice

var color = ["red", "green", "blue", "yellow"];
const newArray = [...color];
newArray.splice(2, 1);
console.log(newArray);

If I got it right what you want, so show everything EXCEPT the one which's index you pass, then:

myFun = (myArray, n) => {
  return myArray.slice(0, n).concat(myArray.slice(n+1))
}
color = ["red", "green", "blue", "yellow"]
myFun(color, 2)

// ["red", "green", "yellow"]

From what I can infer from your question is - you wish to pass in an index and get everything from the array except for the element at the index you passed, and whether there's a direct array helper that we can use. I think there's none so you might as well want to create your own :D

Array.prototype.invertedArrayWithIndex = function(indexOfChoice){
        var _array = this;
        return _array.filter(function(ele, index){
         return _array.indexOf(ele) !=  indexOfChoice
    })
}

var color = ["red", "green", "blue", "yellow"];

color.invertedArrayWithIndex(2); // Array(3) [ "red", "green", "yellow" ]