how to assign multiple variable value from key value of dict in python?

Question

here HEX2RGB return dict value after conversion like {r:255,g:255,b:255}

    rgbValue=HEX2RGB(hex,'dict')
    r,g,b={rgbValue} # not working

so how can I assign value of each key r,g,b in the variables r,g,b like above method? or is there any other efficient way?

@Epsi95: Perhaps you should place this as an answer. You should avoid answering questions in comments. — Sylvester is on codidact.com
– Sylvester is on codidact.com, Commented Sep 5, 2021 at 15:05
Does HEX2RGB already support producing a tuple (seems like it supports something, since 'dict' is an argument rather than a hard-coded assumption)? — chepner
– chepner, Commented Sep 5, 2021 at 15:11
@SamMatzko sure, but I want to correct one thing, we should not rely on python dict order (although 3.6+ it is ordered, but we can assume python version beforehand), so it might not be surprising that rgbValue.values() can give (b,g,r), (g,b,r) etc, I think Roman's first answer is good one. More fancy and unnecessary one can be r,g,b = map(rgbValue.__getitem__, ('r', 'g', 'b')) — Epsi95
– Epsi95, Commented Sep 5, 2021 at 15:21

chepner · Accepted Answer · 2021-09-05 15:09:36Z

5

Use operator.itemgetter, which will not rely on any particular ordering returned by HEX2RGB;

from operator import itemgetter

dictToTuple = itemgetter('r', 'g', 'b')

r, g, b = dictToTuple(HEX2RGB(hex,'dict'))

answered Sep 5, 2021 at 15:09

chepner

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2 Comments

Roman Over a year ago

your solution is a little overengineerd for this specific case. It's still a very good answer. I did not know the itemgetter until now. Thanks for showing the operator module!

chepner Over a year ago

I would not call this overengineered. It puts a single function from the standard library to its intended use, is more efficient than three separate calls to get, and makes no assumptions about the order of the keys in the dict argument.

Roman · Accepted Answer · 2021-09-05 15:03:48Z

2

if your type is a dictionary (assumption cause you wrote {r:255,g:255,b:255})

r,g,b = rgbValue.get('r'),rgbValue.get('g'),rgbValue.get('b')

More Pythonic way:

dict = {'r':255,'g':255,'b':255}
r,g,b = dict.values()

print(r)
print(g)
print(b)

answered Sep 5, 2021 at 15:03

Roman

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3 Comments

Mad Physicist Over a year ago

Most pythonic way would be to not name your dictionary dict to avoid shadowing the class

Roman Over a year ago

@MadPhysicist true, that's a very good comment. I had not thought of that.

Thierry Lathuille Over a year ago

Note that your second solution only works if the dict keys were created in the specific order r, g, b for versions of Python >= 3.7 where dicts are ordered, and will randomly fail for older versions.

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