Validation HTML Radio Button

Question

I am facing a problem with simple validating of radio button though database.

What I want to do is to just simply check whether radio button for each question is selected or not. I know the simple checking. But as I am using php variable name for every radio button name, it's very hard to convert to javascript variable and check. And I am stuck at this point.

<form id="formID" method="post" action="user_anger_quiz.php?rating_finished=true">

<input type="radio" name="<?php echo $question_form_name; ?>" value="<?php echo $question_id ?>,1"/>
<input type="radio" name="<?php echo $question_form_name; ?>" value="<?php echo $question_id ?>,2" />

<p id="anger_rating_submit">
<input type="submit" value="Rate my anger level"/></p>
  </form>

Any suggestions would be appreciated in advanced.

Can you give us a little more info on what you mean. Are you checking the radio buttons against correct answers in a db table? or checking them statically. Or when you say validating, do you mean that your code is broken? Can we see some more output? — Tim Joyce
– Tim Joyce, Commented Aug 2, 2011 at 15:15
I want to check the users check the radio button or not. thx — Ye Lin Aung
– Ye Lin Aung, Commented Aug 2, 2011 at 15:21
You would need to use some javascript. This thread should get you started : stackoverflow.com/questions/2325924/… — Tim Joyce
– Tim Joyce, Commented Aug 2, 2011 at 15:28

Talisin · Accepted Answer · 2011-08-02 15:30:14Z

1

regarding to your comment:

I guess that you will use php to check it due to the fact that you just add php as a tag. In php you can use $_POST or $_GET on action page of your form to fetch the radio buttons.

Otherwise you can use javascript / javascript library

answered Aug 2, 2011 at 15:30

Talisin

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Aaron W. · Accepted Answer · 2011-08-02 15:34:20Z

1

I think you're asking to make sure there is a radio button checked before submitting? Try the below untested function using jquery to see if there is a radio button selected. Run that before the form is submitted.

function somethingChecked()
{
    if (!$("input[name='<?php echo $question_form_name; ?>']:checked").val()) {
        alert('You need to check something');
        return false;
    } else {
        return true;
    }
}

answered Aug 2, 2011 at 15:34

Aaron W.

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