How to push to an array values from inside an arrow function

Question

I'm trying to push to an array even numbers inside an arrow function but I don't how to push it in to that array.

My code:

var arrayEvenNumbers = [];
var evenNumbers = (arrayEvenNumbers) => {
  for (i = 2; i <= 20; i++) {
    if (i % 2 == 0) {
      arrayEvenNumbers.push(i);
    }
  }
}
console.log(evenNumbers(arrayEvenNumbers));

Really I'm a beginner and I've learned a bit, but I'm trying my best

Hope someone could help me to improve

Also I don't know if I'm sending the arguments properly And I'm not native english speaker so excuse if I can't express correctly :)

You're not returning anything. In EvenNumbers return arrayEvenNumbers; after your loop. — StackSlave
– StackSlave, Commented Oct 7, 2021 at 1:59

Mister Jojo · Accepted Answer · 2021-10-07 02:02:03Z

2

this way

var arrayEvenNumbers = [];

const evenNumbers = arr =>
  {
  for (let i = 2; i <= 20; i++)  
    if (i % 2 == 0)  arr.push(i);
 
  return arr
  }

console.log( evenNumbers(arrayEvenNumbers) )

console.log( arrayEvenNumbers )

answered Oct 7, 2021 at 2:02

Mister Jojo

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1 Comment

Alvaro Fierro Over a year ago

Thanks man, it{s so helpful

DemiPixel · Accepted Answer · 2021-10-07 01:48:31Z

1

evenNumbers pushes it correctly, but returns undefined. You're probably looking to do:

evenNumbers(arrayEvenNumbers);
console.log(arrayEvenNumbers);

answered Oct 7, 2021 at 1:48

DemiPixel

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1 Comment

Alvaro Fierro Over a year ago

Ye, that's what I forgot, thanks

Muhammad_محمد · Accepted Answer · 2021-10-07 13:24:54Z

1

this is the code you've forgotten the return statement:

var freeArr = [];
var evenNumbers = (arr)=>{
    for(i = 2; i <= 20; i++){
        if(i % 2 == 0){
            arr.push(i);
        };
    };
    return(arr);
};
console.log(evenNumbers(freeArr));

answered Oct 7, 2021 at 13:24

Muhammad_محمد

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