How to replace all occurrences inside an object?

Question

I have an object like this:

users = [{
  "userid": "1",
  "fornonmods": "<div id=\"user1\" data-login=\"\" data-status=\"online\" class=\"item\">",
  "formods": "<div id=\"user1\" data-login=\"\" data-status=\"online\" class=\"item\">"
}, {
  "userid": "19917",
  "fornonmods": "<div id=\"user19917\" data-login=\"kBr4pelyDy4yKVmiAAAD\" data-status=\"online\" class=\"item\">",
  "formods": "<div id=\"user19917\" data-login=\"kBr4pelyDy4yKVmiAAAD\" data-status=\"online\" class=\"item\">"
}];

I want to replace all the occurrences of
data-login=\"kBr4pelyDy4yKVmiAAAD\" data-status=\"online\"
with
data-login=\"kBr4pelyDy4yKVmiAAAD\" data-status=\"gagged\"
just like I would do with replace() but the thing is that that only works with strings and I am not allowed to convert this object into a string.
What can I do in this cases?

so loop over the array and replace the strings. users.forEach — epascarello
– epascarello, Commented Oct 25, 2021 at 17:58
@CainNuke you don't want to "replace anywhere in object", but in each .fornonmods property of the objects in the array. You know how to iterate an array? — Bergi
– Bergi, Commented Oct 25, 2021 at 18:02
not only in fornonmods but also in formods and all others i didnt include for the sake of convinience. — Cain Nuke
– Cain Nuke, Commented Oct 25, 2021 at 18:04
@CainNuke But surely not in userids? So list the properties explicitly that you want to process. — Bergi
– Bergi, Commented Oct 25, 2021 at 18:05

Ran Turner · Accepted Answer · 2021-10-25 18:43:54Z

1

map is what you're looking for

const users = [{
  "userid": "1",
  "fornonmods": "<div id=\"user1\" data-login=\"\" data-status=\"online\" class=\"item\">",
  "formods": "<div id=\"user1\" data-login=\"\" data-status=\"online\" class=\"item\">"
}, {
  "userid": "19917",
  "fornonmods": "<div id=\"user19917\" data-login=\"kBr4pelyDy4yKVmiAAAD\" data-status=\"online\" class=\"item\">",
  "formods": "<div id=\"user19917\" data-login=\"kBr4pelyDy4yKVmiAAAD\" data-status=\"online\" class=\"item\">"
}];

const id = "kBr4pelyDy4yKVmiAAAD";

const res = users.map(x => {
   const container = {};

   container.userid = x.userid,
   container.fornonmods = x.fornonmods.replace(`data-login=\"${id}\" data-status=\"online\"`, `data-login=\"${id}\" data-status=\"gagged\"`);
   container.formods = x.formods.replace(`data-login=\"${id}\" data-status=\"online\"`, `data-login=\"${id}\" data-status=\"gagged\"`);

   return container;
});

console.log(res);

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map

edited Oct 25, 2021 at 18:43

answered Oct 25, 2021 at 18:30

Ran Turner

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5 Comments

Cain Nuke Over a year ago

Can I also use a variable for kBr4pelyDy4yKVmiAAAD?

Ran Turner Over a year ago

Yes, just use template literals my friend. string text ${yourVar} string text developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

Ran Turner Over a year ago

I changed the answer for your request with a const id (kBr4pelyDy4yKVmiAAAD)

Cain Nuke Over a year ago

it works, thank you!

Ran Turner Over a year ago

You're most welcome my friend

marvinav · Accepted Answer · 2021-10-25 18:19:22Z

1

You need to iterate over users and replace with regex pattern.

const searchString = new RegExp('data-login=\"kBr4pelyDy4yKVmiAAAD\" data-status=\"online\"', 'g');
const replacement = 'data-login=\"kBr4pelyDy4yKVmiAAAD\" data-status=\"gagged\"';
const parsedUsers = users.map(x=>{
  return {
    userid: x.userid,
    fornonmods: x.fornonmods.replace(searchString,replacement),
    formods: x.formods.replace(searchString,replacement)
 }
})

answered Oct 25, 2021 at 18:19

marvinav

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3 Comments

Cain Nuke Over a year ago

great, but can I use also a variable instead of kBr4pelyDy4yKVmiAAAD?

marvinav Over a year ago

Of course, just use string concatenation. const searchString = new RegExp(data-.... ${variable}... , 'g')°

Cain Nuke Over a year ago

Thank you, that was very helpful.

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