How to convert string into numbers in python

Question

I see an interesting python exercise in codewars.it is about convert strings to numbers.I want some suggestions or guidance to solve this python exercise.Thank you

this is the exercise:In this kata we want to convert a string into an integer. The strings simply represent the numbers in words. Examples: "one"1

and this is my code:

def parse_int(string):
    dict_of_numbers={ "zero":0, "one":1, "two":2, "three":3, "four":4, "five":5, "six":6, "seven":7, "eight":8, "nine":9,"ten":10, "eleven":11, "twelve":12, "thirteen":13, "fourteen":14, "fifteen":15, "sixteen":16, "seventeen":17, "eighteen":18, "nineteen":19, "twenty":20, "thirty":30, "forty":40, "fifty":50, "sixty":60, "seventy":70, "eighty":80, "ninety":90,"thousand":1000,"hundred":100}

    string=string.replace(' ','-')
    numbers=string.split('-')
    created_number=0
    for number in numbers:
        for key,value in dict_of_numbers.items():
            if number==key:
                created_number+=value
    return created_number

it doesn't work for big numebrs.for example seven hundred eighty-three thousand nine hundred and nineteen — M.HBA
– M.HBA, Commented Oct 26, 2021 at 11:24
You are assuming the spoken numbers are summed up. However in some situations they are multiplied. For example seven hundred. You must multiply the number before the hundred with 100. — niaei
– niaei, Commented Oct 26, 2021 at 11:28
May have a look at how the developer of word2number solved this, as the translation from spoken numbers to integers is not that easy due to the issue @MSH mentioned: GitHub — user8563312
– user8563312, Commented Oct 26, 2021 at 11:33

niaei · Accepted Answer · 2021-10-26 11:50:20Z

I have a solution and I did not test it for large collection of numbers but it may give you some ideas:

Spoken numbers sometimes are summed sometimes are multiplied.
Some times people put an and between numbers. Like: thirty seven thousand and twenty one
Don't use [] to get value from your dictionary. Use get method. So if there is not data corresponding to the number you have control over the return.
use str's .lower() to lower the letters in the string to avoid upper case, lower case problem

The code I wrote would look like:

def parse_int(string):
    dict_of_numbers = {"zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7,
                       "eight": 8, "nine": 9, "ten": 10, "eleven": 11, "twelve": 12, "thirteen": 13, "fourteen": 14,
                       "fifteen": 15, "sixteen": 16, "seventeen": 17, "eighteen": 18, "nineteen": 19, "twenty": 20,
                       "thirty": 30, "forty": 40, "fifty": 50, "sixty": 60, "seventy": 70, "eighty": 80, "ninety": 90,
                       "thousand": 1000, "hundred": 100}

    string = string.replace(" and ", " ")
    the_number = 0
    for each in string.lower().split():
        if each in ["hundred", "thousand"]:
            the_number *= dict_of_numbers.get(each, 1)
        else:
            the_number += dict_of_numbers.get(each, 0)


    return the_number


print(parse_int("thirty seven thousand and twenty two")) # 37022

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