How to get url out of the style tag using selenium in python

Question

I am trying to get this url out of this line but i have no idea how to get it :-

<div class="photo" style="background-image: url(&quot;https://images.deliveryhero.io/image/fd-bd/Products/1032643.jpg?width=200&quot;);"></div>

it is inside this :-

<picture data-testid="menu-product-image" style="background-image: url(&quot;https://micro-assets.foodora.com/img/logo-simple-fp.svg&quot;);"><div class="photo" style="background-image: url(&quot;https://images.deliveryhero.io/image/fd-bd/Products/1032643.jpg?width=200&quot;);"></div></picture>

thanks

Pedro Maia · Accepted Answer · 2021-10-27 19:40:29Z

1

Try this:

url = driver.find_element_by_class_name("photo").value_of_css_property("background-image")[9:-2]

answered Oct 27, 2021 at 19:40

Pedro Maia

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