Implicit convert CString to char*

Question

I have downloaded an sample code, so there are some CString variables in that code which are passed to the sscanf() function as char* the compiler implicitly converts those CString and the code complie fine.the code which works fine is here:

CString m_strVersionXFS;
m_strVersionXFS = _T("00029903");

DWORD nVersion;
sscanf(m_strVersionXFS,"%08X",&nVersion);

the problem is here when i tried to write my own simple code which tries to manipulate a CString variable in the same way but the compiler says which can't convert a CString to a cahr*

just some minor correction: It is const char*, not char*. You can't make it non-const. — J-16 SDiZ
– J-16 SDiZ, Commented Aug 8, 2011 at 7:06

Sven · Accepted Answer · 2011-08-08 05:54:44Z

3

I suspect that your own code is using unicode (UNICODE constant defined). This means that CString is using wide characters, and will implicitly convert to wchar_t*, but not to char*.

If that is the case, there are three possible solutions:

Use swscanf, the wide character version of sscanf (recommended);
Explicitly use CStringA instead of CString so you're using the ANSI version of CString;
Change your project to use multi-byte characters rather than unicode (this can be done from the project properties in Visual Studio).

answered Aug 8, 2011 at 5:54

Sven

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