Compare two arrays of objects; If second object contains the same key/value as the first return the second's, if not add key/value from the first

Question

Consider the following: We have two arrays, each with an object.

let users: [
  {
    "id": "some#"
    "name": "some name",
    "data": "somedata"
  }
],


let products: [
    {
      "product": "some#"
      "name": "abc",
    },
]

Essentially compare both objects, if the second object has the same property as the first, keep the second prop and value if not add the prop/value from the first.

So the output is :

{
  "id": "some#",
  "name": "abc",
  "data": "somedata"
}

Amit Hagag · Accepted Answer · 2021-11-15 18:53:44Z

1

Try this:

if (!(users[0].name === products[0].name)) {
product[0].data = users[0].data
}

answered Nov 15, 2021 at 18:53

Amit Hagag

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Comments

Youssouf Oumar · Accepted Answer · 2022-06-22 21:26:09Z

1

With the code below, for the data you have given, you can have that output you are looking for:

let users = [
  {
    id: "some#",
    name: "some name",
    data: "somedata"
  }
];

let products = [
  {
    product: "some#",
    name: "abc"
  }
];

for (key in users[0]) {
  if (products[0][key]) {
    users[0][key] = products[0][key];
  } else {
    continue;
  }
}
console.log(users);

edited Jun 22, 2022 at 21:26

answered Nov 15, 2021 at 18:53

Youssouf Oumar

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