PHP catch eval output

Question

I wanna catch the output of the eval execution and see only the output of $B , any solution for that?

If i execute the code like this i get output twice:

first from eval

second from $B

pls i dont need questions why i am using eval, and that eval is evil.

I need a solution for exactly this example.

<?php
  $A = '<?php echo "Output"; ?>';
  eval(" ?> $A <?php ");
  $B = ob_get_contents();
  echo $B;
?>

AbraCadaver · Accepted Answer · 2021-11-19 16:13:02Z

5

You didn't show it so you need to start buffering with ob_start. Then get and clean the buffer so that the buffer will be empty at the end of execution ob_get_clean:

<?php
  ob_start();
  $A = '<?php echo "Output"; ?>';
  eval(" ?> $A <?php ");
  $B = ob_get_clean();
  echo $B;
?>

Alternately you could use ob_clean or ob_end_clean somewhere after the ob_get_contents.

edited Nov 19, 2021 at 16:13

answered Nov 19, 2021 at 16:05

AbraCadaver

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