I have a list of strings in this format:
my_strings = [
"10.02.20 time 09.24",
"06.02.20 time 08.51",
"10.02.20 time 09.24",
"10.02.20 time 09.25",
"10.02.20 time 09.26",
"10.02.20 time 09.27",
"10.02.20 time 09.28",
"10.02.20 time 09.29"
]
How can I sort them based on date and time, both normally and reversely? I think I should use something like:
my_strings.sort(key=lambda date: datetime.strptime(date, "%d-%b-%y"))
But this doesn't work.
Assuming your format is "day.month.year time hour.minute", you need:
my_strings.sort(key=lambda date: datetime.strptime(date, '%d.%m.%y time %H.%M'))
If by "normally and reverse" you mean in ascending and descending order, for the latter you can either reverse the sorted list with my_strings[::-1], or directly while sorting with my_strings.sort(key=..., reverse=True).
my_strings to "10.02.19 time 09.29".
As per the documentation for the strptime function, the correct call for the function is:
strptime(date, "%d.%m.%y time %H.%M")
The %b you put in your code is for "Month as locale’s abbreviated names (Jan, Feb, …, Dec), but the correct is %m for "Month as a zero-padded decimal number", and you also need to include time %H.%M in the string declaring the format for it to work, or else you will get an ValueError: time data '10.02.20 time 09.24' does not match format '%d.%b.%y'
my_strings.sort() should work!the statement you import into the datetime module may be import datetime, try from datetime import datetime.
it is all code
from datetime import datetime
my_strings = [
"10.02.20 time 09.24",
"06.02.20 time 08.51",
"10.02.20 time 09.24",
"10.02.20 time 09.25",
"10.02.20 time 09.26",
"10.02.20 time 09.27",
"10.02.20 time 09.28",
"10.02.20 time 09.29"
]
my_strings.sort(key=lambda date: datetime.strptime(date, "%y.%m.%d time %H.%M"))
print(my_strings)
