Python OOP, how to keep adding a number Instance attribute?

Question

Trying to deposit into the wallet, it worked the first call, then when I call the deposit function again it would give me the error.
TypeError: 'int' object is not callable Any solutions to this?

class Bank():

    def __init__(self,wallet):
        self.wallet = wallet

    def withdraw(self,withdraw):
        self.withdraw = withdraw

    def deposit(self, deposit):
        self.deposit = deposit
        self.wallet += self.deposit




bank = Bank(0)

bank.deposit(500)
print(bank.wallet)
bank.deposit(500)
print(bank.wallet)

Why did you do self.deposit = deposit? Once you've done that bank.deposit is not a method any more, it's an int. — khelwood
– khelwood, Commented Nov 22, 2021 at 22:24
I was assuming that each time I create a function in a class that I would need to the self. for each variable. — Vimalan Karunakaran
– Vimalan Karunakaran, Commented Nov 22, 2021 at 22:26
You see lines like that in __init__ methods frequently because __init__ is where you define all the attributes of an object, but you usually don't want to set new attributes outside of __init__, nor do all the attributes set in __init__ need to be 1:1 with the function arguments. For example, your Bank.__init__ could just always set self.wallet = 0 to start with and not require a wallet argument at all. — Samwise
– Samwise, Commented Nov 22, 2021 at 22:39
Ah, okay I'll keep a note of that, thank you very much for clarifying this! — Vimalan Karunakaran
– Vimalan Karunakaran, Commented Nov 22, 2021 at 22:43

Joe · Accepted Answer · 2021-11-22 22:23:34Z

2

You're reassigning your deposit function to an integer in the line. self.deposit = deposit. Remove that :)

answered Nov 22, 2021 at 22:23

Joe

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1 Comment

j1-lee Over a year ago

With the same logic, remove self.withdraw = withdraw.

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