firebase deploy to custom region for scheduled functions

Question

I successfully managed to deploy my https.onCall() cloud functions on a specific server location with

functions.region("europe-west6")
.https.onCall((data, context) => ...

But when I tried to specify a location for scheduled function:

   exports.getItems = functions.pubsub.schedule('0 6 * * *')
  .region("europe-west6")
  .timeZone('Europe/Zurich')
  .onRun(async (context) => {

I receive:

TypeError: functions.pubsub.schedule(...).region is not a function

I wonder if this functionality (defining custom deploy region) is not available for scheduled functions...

(btw deploying the scheduled function worked without the .region() parameter)

Dharmaraj · Accepted Answer · 2021-11-27 13:16:46Z

2

The .region() exists on imported functions SDK itself and not on the ScheduleBuilder returned by .schedule(), try this:

exports.getItems = functions.region("europe-west6")
  // after .region(''), similar to the HTTP function
  .pubsub.schedule('0 6 * * *')  
  .timeZone('Europe/Zurich')
  .onRun(async (context) => {

  })

answered Nov 27, 2021 at 13:16

Dharmaraj

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1 Comment

Yves Boutellier Over a year ago

Oh thank you very much! how could I miss that..

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