This is my code:
var shuffle = function(x) {
var deck = [];
deck.push(x);
return deck;
};
var Placemat = function() {
var card1 = deck.shift();
var card2 = deck.shift();
}
By returning deck in shuffle() like this, can I use it in Placemat()? If not, how can I do it?
Yes you could. But anytime you call .shuffle() you would overwrite that array, or more precisely, create a new instance. So if you want to keep that reference you could go like
var shuffle = (function() {
var deck = [];
return function(x) {
deck.push(x);
return deck;
};
}());
Now .shuffle() closes over the deck by returning another function. So it could look like
var Placemat = function() {
var myDeck = shuffle(5);
shuffle(10);
shuffle(15);
var card1 = deck.shift();
var card2 = deck.shift();
}
Even if that is probably not the greatest way to go. But I guess I don't even know what exactly you want to achieve there.
myDeck.shift() ?You cannot you have to put them in the parameters or outside the function.
var shuffle = function(x) {
var deck = [];
deck.push(x);
return deck;
};
var Placemat = function(deck) {
var card1 = deck.shift();
var card2 = deck.shift();
}
or
var deck = [];
var Placemat = function() {
var card1 = deck.shift();
car card2 = deck.shift();
}
You can use the return value from shuffle in Placemat, but it will always be an array with a single item in it.
If you want to have a variable deck that contains multiple items, deck will need to be declared in an outer scope:
var deck = [];
var shuffle = function(x) {
deck.push(x);
return deck;
}
var Placemat = function() {
var card1 = deck.shift();
var card2 = deck.shift();
};
This way, both the shuffle function and Placemat are using the same variable deck.
I found another solution:
var shuffle = function(deck,x) {
var deck = [];
deck.push(x);
return deck;
};
var Placemat = function() {
var newdeck = shuffle(deck,x)
var card1 = newdeck.shift();
var card2 = newdeck.shift();
}
This way I don't have to make deck a global variable. Thanks for the help everyone.