Filter object by value [duplicate]

Question

Let's say I have:

let object1 = [{id: 15, name: name1}, {id: 0, name: name2}, {id: 98, name: name3}];
let object2 = [{id: 2, action: action}, {id: 88, action: action}, {id: 0, action: action}];

ID numbers don't match on purpose. How could I get name values from object1 whose ID's don't appear in object2?

Edit: I've tried to

let results;
for (let i = 0; i < object1.length; i++) {
         results = object2.filter(element => { return element.id != object1[i].id } );
    }

Also tried to get it working with .map(), but with no luck.

Your question sounds actually like you haven't try anything and expect a free code service. This is going to be really badly welcomed. If you've tried anything, please show us your attempts — Cid
– Cid, Commented Dec 2, 2021 at 20:16
Oh sorry about that. Let me go through something that I've tried so far! Editing the original post. — Ville
– Ville, Commented Dec 2, 2021 at 20:16

axtck · Accepted Answer · 2021-12-02 20:40:48Z

3

You could use filter() on one of the arrays and find() to filter out the objects from that array with ids that don't occur in the other array.

let oArr1 = [{id: 15, name: "name1"}, {id: 0, name: "name2"}, {id: 98, name: "name3"}];
let oArr2 = [{id: 2, action: "action"}, {id: 88, action: "action"}, {id: 0, action: "action"}];

const result = oArr1.filter(x => !oArr2.find(y => y.id === x.id));

console.log(result);

edited Dec 2, 2021 at 20:40

answered Dec 2, 2021 at 20:30

axtck

3,9753 gold badges17 silver badges32 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Filter object by value [duplicate]

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related