Java relative path in NetBeans

Question

I am developing a NetBeans module where I have a Java package called testand another package called test.templates. I want to read a text file which is in the test.templates package from a Java file in the test package. I tried in several ways, but it gives a FileNotFoundException exception:

BufferedReader br = new BufferedReader(new FileReader("templates/test.txt"));
BufferedReader br = new BufferedReader(new FileReader("/test/templates/test.txt"));
BufferedReader br = new BufferedReader(new FileReader("src/test/templates/test.txt"));

But none of these worked.. I want to use the relative path, not the absolute path. What should I do?

Ray Toal · Accepted Answer · 2011-08-12 06:47:19Z

4

You will want to use getResource or getResourceAsStream.

Example on java2s.com:

http://www.java2s.com/Code/Java/Development-Class/Loadresourcefilerelativetotheclasslocation.htm

answered Aug 12, 2011 at 6:47

Ray Toal

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Kristijan Iliev · Accepted Answer · 2015-07-11 12:37:22Z

3

You should note somethings about relative path (Netbeans):

+ File: Default is project folder, means outside of src folder.
If you save to test.txt, it will generate: project/test.txt.
If you save to data/test.txt, ... project/data/test.txt
So if you want to load file, you just do it conversely. Like this, you should put your files in project/data/filename.txt. Then when code, you get path: data/filename.txt.

+ ImageIcon: I will share later if can.
+ Image(SplashScreen): I will share later.

edited Jul 11, 2015 at 12:37

Kristijan Iliev

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answered Jul 11, 2015 at 11:45

Vũ Hồng Kỳ

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1 Comment

Cuong Nguyen Over a year ago

I'm not sure about this answer :v

Megatron · Accepted Answer · 2013-11-01 15:36:06Z

1

getResource() returns a URL, so to extract the filename, you can try calling getFile().

The filepath you pass to getResource will be based on your netbeans package. Use a leading slash to denote the root of the classpath.

Example:

getResource(/db_files/table.csv).getFile()

answered Nov 1, 2013 at 15:36

Megatron

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Comments

Joyal Augustine · Accepted Answer · 2012-08-21 10:10:06Z

0

try
{
BufferedReader br = new BufferedReader(new FileReader(getClass().getResource("/test/templates/test.txt").toString().substring(6)));
}
catch(Exception ee)
{
JOptionPane.showMessageDialog(this, ee);   
}

answered Aug 21, 2012 at 10:10

Joyal Augustine

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