How to get objects by searching the array content

Question

I have this object

let obj = [
   {name: 'title 1', values:['test 1', 'test 2']},
   {name: 'title 2' values: ['test 3', 'test 4']}
]

I want to search for values = 'test 3' and it will return objects contaning that skills ouput: {name: 'title 2' values: ['test 3', 'test 4']}

I have tried searching like obj.find(c=> c.skills), iteration etc. but it only works not inside the array of objects.

do you want an array of objects or a single object?

Nina Scholz
– Nina Scholz

2021-12-23 14:37:17 +00:00
Commented Dec 23, 2021 at 14:37 — Nina Scholz
– Nina Scholz, Commented Dec 23, 2021 at 14:37
Is your question answered?

connexo
– connexo

2022-01-14 20:14:16 +00:00
Commented Jan 14, 2022 at 20:14 — connexo
– connexo, Commented Jan 14, 2022 at 20:14

Mureinik · Accepted Answer · 2021-12-23 14:31:16Z

1

I'd use filer to apply a condition on values:

 let obj = [
   {name: 'title 1', values:['test 1', 'test 2']},
   {name: 'title 2', values: ['test 3', 'test 4']}
];

const result = obj.filter(o => o.values.includes('test 3'));

console.log(result);

answered Dec 23, 2021 at 14:31

Mureinik

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Comments

Nina Scholz · Accepted Answer · 2021-12-23 14:32:21Z

0

You could find the object by looking into the array with Array#includes.

const
    objects = [{ name: 'title 1', values: ['test 1', 'test 2'] }, { name: 'title 2', values: ['test 3', 'test 4'] }],
    value = 'test 3',
    result = objects.find(({ values }) => values.includes(value));

console.log(result);

answered Dec 23, 2021 at 14:32

Nina Scholz

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1 Comment

connexo Over a year ago

This will only return the first match.

connexo · Accepted Answer · 2021-12-23 14:32:21Z

0

Use filter:

let obj = [{
  name: 'title 1',
  values: ['test 1', 'test 2']
}, {
  name: 'title 2',
  values: ['test 3', 'test 4']
}];

let skill = 'test 3';
let result = obj.filter(c => c.values.includes(skill));

console.log(result);

answered Dec 23, 2021 at 14:32

connexo

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Comments

Tushar Shahi · Accepted Answer · 2021-12-23 14:36:33Z

0

filter() and indexOf() should do it.

let obj = [
   {name: 'title 1', values:['test 1', 'test 2']},
   {name: 'title 2', values: ['test 3', 'test 4']}
];
    
    let ans = obj.filter(x => x.values.indexOf('test 3') > -1);
    console.log(ans);

answered Dec 23, 2021 at 14:36

Tushar Shahi

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Comments

Maik Lowrey · Accepted Answer · 2021-12-23 14:39:19Z

0

filter with includes already done. find with includes already done. Then i show the forEach version today ;-)

obj = [{
  name: 'title 1',
  values: ['test 1', 'test 2']
}, {
  name: 'title 2',
  values: ['test 3', 'test 4']
}];

n = []
obj.forEach(c => {
  if (c.values.includes('test 3')) {
    n.push(c)
  }
})

console.log('new', n)

answered Dec 23, 2021 at 14:39

Maik Lowrey

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