How do I output the result generated in if-loop as one array?

Question

I have my data as an array, and I want to extract every 7th value in the data. My code is like this:

import numpy as np

n=np.arange(0,100,1)
data=np.array(np.arange(0,100,1))

for n in n:
    if n%7==0:
        array=data[n]

But instead of one array, the 'array' in this output is actually a collection of single int objects(I would like to do this for float objects as well) that were looped over. How can I output one array or is if-loop not the way to do it?

@joshmeranda Sorry, I should edit my post: I get a collection of single integer/float objects, not arrays. — Limona2000
– Limona2000, Commented Dec 28, 2021 at 21:02

Constantin Guidon · Accepted Answer · 2021-12-28 21:04:19Z

1

You can simply do this:

import numpy as np

n=np.arange(0,100,1)
data=np.array(np.arange(0,100,1))
data[::7]

for more informations: Understanding slice notation

answered Dec 28, 2021 at 21:04

Constantin Guidon

1,89218 silver badges22 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

Limona2000 Over a year ago

Yes! That's exactly what I'm looking for. Thanks!

Limona2000 Over a year ago

The slice notation also seems very useful. I'll have a good read for sure.

mozway Over a year ago

@Limona2000 if the answer is exactly what you need, consider accepting it ;)

Limona2000 Over a year ago

@mozway Good call, just didd! Sorry, just started using this :)

Collectives™ on Stack Overflow

How do I output the result generated in if-loop as one array?

1 Answer 1

4 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

4 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related