Python number rounding depends on the number

Question

In python, I am using rounding to 1 decimal. But If a number is 0.03 or 0.005, then It should show until the last number in the decimal places.

def calculate_total(number):
   # some number calcualtions
   number = round(number, 1)
   print(number)
   

calculate_total(66.36) # 66.4
calculate_total(3.34) # 3.3
calculate_total(3.34) # 3.3
calculate_total(0.03) # 0.0 (But it should show 0.03)
calculate_total(0.0364) # 0.0 (But it should show 0.04)

Sibtain Reza · Accepted Answer · 2022-01-13 05:35:16Z

3

That is because you are rounding the float to one decimal place in z = 0.03 and z = 0.0364

Just change print(round(z, 1)) to print(round(z, 2)) ; this will change the decimal place from 1 to 2 and it will produce your required output.

answered Jan 13, 2022 at 5:35

Sibtain Reza

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2 Comments

Smith Dwayne Over a year ago

My early question was misleading. Sorry. I updated my question now.

Sibtain Reza Over a year ago

Still the answer of the question remains the same.

Park · Accepted Answer · 2022-01-13 05:46:28Z

0

You can use this type of code, providing your own condition.

In the following code, a rounding place is different depending on whether z variable is one of the value of (0.03, 0.005) or not.

z = 66.36
result = round(z, 2)

l = (0.03, 0.005)
if result in l:
    print(round(result, 1))
else:
    print(round(result, 2))

answered Jan 13, 2022 at 5:46

Park

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