Dart RegEx is not splitting String

Question

Im a fresher to RegEx. I want to get all Syllables out of my String using this RegEx: /[^aeiouy]*[aeiouy]+(?:[^aeiouy]*\$|[^aeiouy](?=[^aeiouy]))?/gi

And I implemented it in Dart like this:

void main() {
  String test = 'hairspray';
  final RegExp syllableRegex = RegExp("/[^aeiouy]*[aeiouy]+(?:[^aeiouy]*\$|[^aeiouy](?=[^aeiouy]))?/gi");
  print(test.split(syllableRegex));
}

The Problem: Im getting the the word in the List not being splitted. What do I need to change to get the Words divided as List.

I tested the RegEx on regex101 and it shows up to Matches. But when Im using it in Dart with firstMatch I get null

Wiktor Stribiżew · Accepted Answer · 2022-01-25 13:19:22Z

3

You need to

Use a mere string pattern without regex delimiters in Dart as a regex pattern
Flags are not used, i is implemented as a caseSensitive option to RegExp and g is implemented as a RegExp#allMatches method
You need to match and extract, not split with your pattern.

You can use

String test = 'hairspray';
final RegExp syllableRegex = RegExp(r"[^aeiouy]*[aeiouy]+(?:[^aeiouy]*$|[^aeiouy](?=[^aeiouy]))?",
                caseSensitive: true);
for (Match match in syllableRegex.allMatches(test)) {
   print(match.group(0));
}

Output:

hair
spray

edited Jan 25, 2022 at 13:19

answered Jan 25, 2022 at 0:42

Wiktor Stribiżew

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2 Comments

lrn Over a year ago

Also likely want $ instead of \$ since the latter matches a literal $, not the end of input.

Wiktor Stribiżew Over a year ago

@lrn Right, in a regular string literal, it was escaped so as to be parsed as a literal $ char.

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