I want to move the zeros of the array to the end of the array, like
zeroesToEnd([1, 2, 0, 0, 4, 0, 5])
[1, 2, 4, 5, 0, 0, 0]
I've tried this
console.log(zeroesToEnd([1, 2, 0, 0, 4, 0, 5]))
function zeroesToEnd(a) {
let counter=0;
let concatarr=[];
for(let i=0; i <= a.length;i++){
if(a[i]===0){
concatarr.push(0);
counter++
}
}
return a.concat(concatarr)
}I think using the filter method satisfies your question, however in the spirit of keeping the answer in line with your attempt, I wanted to include an answer using for loops.
In my answer, I initialize a variable to keep track of the number of zeros that are in the first array. Then, I initialize a new array that is going to hold the desired results.
I have one for loop stepping through the items in the array passed into the function, and if it is zero I increase the count, otherwise I add the item to the newArray. Afterwards, I have another for loop which runs the number of times we counted for zeros, and adds a zero to the end of the newArray.
Please note this does not mutate the original array, but produces a new array.
function zeroesToEnd(a) {
let countOfZeros = 0;
const newArray = [];
for (const item of a) {
if (item === 0) countOfZeros++;
else newArray.push(item);
}
for (let i = 0; i < countOfZeros; i++) {
newArray.push(0);
}
return newArray;
}
console.log(zeroesToEnd([1, 2, 0, 0, 4, 0, 5]));