Docker-compose cant reach second command [duplicate]

Question

I have my docker-compose.yaml file like this:

version: "3"

services:
  app:
    build:
      context: .
      dockerfile: Dockerfile
    ports:
      - "8000:8000"
    volumes:
      - ./app:/app
    command: >
      sh -c "python manage.py runserver 0.0.0.0:8000"
      sh -c "python simple_script.py"

and the problem is that when i run docker-compose up it never reaches the second command ( sh -c "python simple_script.py" ) .

I think this is because the first command sh -c "python manage.py runserver 0.0.0.0:8000" never exits.

Is there a way to run two commands like this?

Run the non-blocking code first, or use two containers, or if both are daemons use a process manager like supervisord. Or run the 2nd command with docker exec... — Klaus D.
– Klaus D., Commented Jan 31, 2022 at 5:04
A container only runs one command, but you can have multiple containers running on the same image. Since in fact the Django server won't exit, if you want to run a second command while that's running you'll need an approach like this. — David Maze
– David Maze, Commented Jan 31, 2022 at 11:21

Mojtaba Arezoomand · Accepted Answer · 2022-01-31 05:17:43Z

4

can you try this one:

sh -c "python manage.py runserver 0.0.0.0:8000 & python simple_script.py"

In linux you can use & to run commands in background.
You can use fg to get back to it.

answered Jan 31, 2022 at 5:17

Mojtaba Arezoomand

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2 Comments

David Maze Over a year ago

This may not be what you're after: when simple_script.py completes, the container will exit, and if the Django server fails for some reason, Docker simply won't notice it. It's typically better to run multiple containers with one process per container.

Mojtaba Arezoomand Over a year ago

The best practice is to run them in multiple containers, but question was something else. @DavidMaze

Saikat Roy · Accepted Answer · 2022-01-31 05:05:28Z

-2

You can write two commands in one line. like this -

sh -c "python manage.py runserver 0.0.0.0:8000 && python simple_script.py"

answered Jan 31, 2022 at 5:05

Saikat Roy

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2 Comments

Klaus D. Over a year ago

This would still block.

Casey Schneider Over a year ago

When I run python3 manage.py runserver 0.0.0.0:8000 && python3 simple_script.py the server begins to run, but the simple_script.py does not run until I quit the server.

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