Calling function from another function

Question

When I call func1 from func2, I get an error. Why is this occurring and how to access the returned dictionary d in func1 from func2?

func1()
NameError: name 'func1' is not defined

class ABC():

    def func1(self, a):
         d = {}
         ###do something with a
         ###return ending dictionary d
         return d

    def func2(self):
         ###Retrieve returned dictionary d from func1 and use
         func1()
         d['key'] = value

d = self.func1() calling a method and setting returned value to d (although you could use a completely different name here, e.g. result = self.func1()) — Lukasz Wiecek
– Lukasz Wiecek, Commented Jan 31, 2022 at 22:38

matszwecja · Accepted Answer · 2022-01-31 22:31:42Z

2

func1 and func2 are instance methods of ABC objects. You need to call them from the instance of such object. In your case, one such instance is self, first parameter of both functions. Thus, self.func1() will work.

answered Jan 31, 2022 at 22:31

matszwecja

8,2372 gold badges13 silver badges22 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Nuno Carvalho · Accepted Answer · 2022-01-31 22:31:44Z

0

Use self.func1() to call the function inside your class.

answered Jan 31, 2022 at 22:31

Nuno Carvalho

3021 silver badge5 bronze badges

Collectives™ on Stack Overflow

Calling function from another function

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related