Parsing xml string containing hyperlink

Question

I am using DOM to parse an XML string as in the following example. This works great except in one instance. The document which I am trying to parse looks like this:

<response requestID=\"1234\">
    <expectedValue>Alarm</expectedValue>
    <recommendations>For steps on how to resolve visit <a href=\"some website\">Website</a> and use the search features for \"Alarm\"<recommendations>
    <setting>Active</setting>
<response>

The code I used to parse the XML is as follows:

try {   
        DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
        InputSource is = new InputSource();
        is.setCharacterStream(new StringReader(xmlResult));

        Document doc = db.parse(is);
        NodeList nlResponse = doc.getElementsByTagName("response");

        String[] String = new String[3];  //result entries

        for (int i = 0; i < nlResponse.getLength(); i++) {
            Element e = (Element) nlResponse.item(i);
            int c1 = 0; //count for string array

            NodeList ev = e.getElementsByTagName("expectedValue");
            Element line = (Element) ev.item(0);
            String[c1] = (getCharacterDataFromElement(line));
            c1++;

            NodeList rec = e.getElementsByTagName("recommendations");
            line = (Element) rec.item(0);
            String[c1] = (getCharacterDataFromElement(line));
            c1++;

            NodeList set = e.getElementsByTagName("settings");
            line = (Element) set.item(0);
            String[c1] = (getCharacterDataFromElement(line));
            c1++;

I am able to parse the code and put the result into a string array (as opposed to the System.out.println()). With the current code, my string array looks as follows:

String[0] = "Alarm"
String[1] = "For steps on how to resolve visit"
String[2] = "Active"

I would like some way of being able to read the rest of the information within "Recommendations" in order to ultimately display the hyperlink (along with other output) in a TextView. How can I do this?

I don't think anyone can answer that without seeing your code (short of writing the while thing for you) — Mat
– Mat, Commented Aug 17, 2011 at 18:06
Sorry... I meant to post this link. My code (for the parsing) looks basically the same. java2s.com/Code/Java/XML/… — Greg
– Greg, Commented Aug 17, 2011 at 18:09
Edit your question to include the relevant parts of your actual code. — Mat
– Mat, Commented Aug 17, 2011 at 18:10
As a sidenote, the source looks odd to me.Usually < and > would be encoded as < and >. This could explain why your parser is doing dodgy stuff. — Philippe
– Philippe, Commented Aug 17, 2011 at 18:15

scott · Accepted Answer · 2011-08-18 01:21:27Z

1

I apologize for my previous answer in assuming your xml was ill-formed.

I think what is happening is that your call to the getCharacterDataFromElement is only looking at the first child node for text, when it will need to look at all the child nodes and getting the href attribute as well as the text for the 2nd child node when looking at the recommendations node.

e.g. after getting the Element for recommendation

            String srec = "";
            NodeList nl = line.getChildNodes();
            srec += nl.item(0).getTextContent();

            Node n = nl.item(1);
            NamedNodeMap nm = n.getAttributes();
            srec += "<a href=\"" + nm.getNamedItem("href").getTextContent() +  "\">" + n.getTextContent() + "</a>";

            srec += nl.item(2).getTextContent();

            String[c1] = srec;

edited Aug 18, 2011 at 1:21

answered Aug 17, 2011 at 19:04

scott

9747 silver badges10 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Don Roby Over a year ago

The current snippet is valid xml.

scott Over a year ago

My mistake, I was under the impression that text couldn't appear within parent nodes alongside its child nodes.

Greg Over a year ago

Thank you! Worked perfectly. FWIW, when using Android, API 8 or higher must be used for getTextContent().

Collectives™ on Stack Overflow

Parsing xml string containing hyperlink

1 Answer 1

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related