I am developing C code on Ubuntu 20.04.
By running cppcheck -q --project=build/proj1/compile_commands.json --file-filter='src/base/Myfile.c'
I got the error
cppcheck: error: unrecognized command line option: "--file-filter=src/base/Myfile.c".
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1 Answer
It looks like the version of cppcheck included in Ubuntu 20.04 is not the latest:
$ apt show cppcheck | grep Version
Version: 1.90-4build1
cppcheck 1.90 was released in 2019. The --file-filter argument was introduced in commit fcd5cda97 in 2020:
$ git show fcd5cda97f10085c7def7fda6fc6199f624010ce
commit fcd5cda97f10085c7def7fda6fc6199f624010ce
Author: fuzzelhjb <[email protected]>
Date: Fri Jan 10 08:57:37 2020 +0100
Check selected files from project (#2378)
diff --git a/cli/cmdlineparser.cpp b/cli/cmdlineparser.cpp
index 3fbc7f6c6..292327051 100644
--- a/cli/cmdlineparser.cpp
+++ b/cli/cmdlineparser.cpp
@@ -376,6 +376,10 @@ bool CmdLineParser::parseFromArgs(int argc, const char* const argv[])
mSettings->xml = true;
}
+ // use a file filter
+ else if (std::strncmp(argv[i], "--file-filter=", 14) == 0)
+ mSettings->fileFilter = std::string(argv[i] + 14);
+
// Only print something when there are errors
else if (std::strcmp(argv[i], "-q") == 0 || std::strcmp(argv[i], "--quiet") == 0)
mSettings->quiet = true;
@@ -1035,6 +1039,9 @@ void CmdLineParser::printHelp()
" --exitcode-suppressions=<file>\n"
" Used when certain messages should be displayed but\n"
" should not cause a non-zero exitcode.\n"
+ " --file-filter=<str> Analyze only those files matching the given filter str\n"
+ " Example: --file-filter=*bar.cpp analyzes only files\n"
+ " that end with bar.cpp.\n"
" --file-list=<file> Specify the files to check in a text file. Add one\n"
" filename per line. When file is '-,' the file list will\n"
" be read from standard input.\n"
The current release version of cppcheck appears to be 2.7.
