Javascript: load with Ajax a javascript and transmit data to it as to a php script

Question

I am loading my script like this:

    var myTestString = "/modules/admin";
    $.ajax({
       type: "GET",
       url: "../../includes/test_tooltip.js",
       data: "module="+myTestString,
       dataType: "script"
     });

Is it possible to have access to module variable in my test_tooltip.js like this?

console.log("I am loaded!" + module);

My scenario is like this. I sometimes need to load that javascript and when i do, i do it in different modules, and i need this javascript to know which module because he will have to do some requests based on the module.

In php i know you can acces data with $_REQUEST["module"], if it could be done in javascript similar would be great.

what's should respond your test_tooltip.js when you launch your query ? — Awea
– Awea, Commented Aug 18, 2011 at 14:13
@Awea : test_tooltip.js will have to put some tooltips on some elements, and the text of that tooltips depends on what parameters i send to it. — Leth
– Leth, Commented Aug 19, 2011 at 11:26
@Ash : It doesn't involve PHP directly, i just need to send some data with that ajax request to the js file, as we do with PHP when making a request. I wished that your code below worked but it doesn't unfortunately. — Leth
– Leth, Commented Aug 19, 2011 at 11:27
I use window.variable and delete window.variable and case closed. Thanks guys! — Leth
– Leth, Commented Aug 19, 2011 at 12:18

Ash Eldritch · Accepted Answer · 2011-08-22 01:45:00Z

1

var myTestString = "/modules/admin";
$.ajax({
   type: "GET",
   url: "../../includes/test_tooltip.js",
   context: { module: myTestString },
   dataType: "script"
 });

Your returned javascript should be executed within scope of the context object given to #.ajax, so you could then do:

console.log("I am loaded!" + this.module);

edited Aug 22, 2011 at 1:45

answered Aug 18, 2011 at 14:27

Ash Eldritch

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2 Comments

Leth Over a year ago

It doesn't work unfortunately. Any more ideas? have you tested it works for you? maybe i am doing something wrong. It says data not defined.

Ash Eldritch Over a year ago

Okay I've modified the answer with an alternative solution

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