passing command line arguments by reference to a function

Question

I want to process command line parameters in seperate function but couldnt pass them. What is the right declaration and definition? And any resource about passing parameters, writing function definition/declaration?

I will use getopt() function in cmd_line() function.

...
...
void cmd_line(*int, *char[]);

int main(int argc, char *argv[]){
    cmd_line(&argc, argv);
    return 0;
}

void cmd_line(int *argc, char *argv[]){
...
...
}

but im taking address of argc argument. And what about pointer array?im getting lots of warn like "implicit declaration" — hepl
– hepl, Commented Feb 13, 2022 at 11:49

klutt · Accepted Answer · 2022-02-13 11:59:27Z

1

Tried to find a duplicate, but did not find any in this context. To make it searchable, here is the relevant error:

main.c:1:15: error: expected declaration specifiers or ‘...’ before ‘*’ token
    1 | void cmd_line(*int, *char[]);
      |               ^
main.c:1:21: error: expected declaration specifiers or ‘...’ before ‘*’ token
    1 | void cmd_line(*int, *char[]);
      |

The problem is that

void cmd_line(*int, *char[]);

should be

void cmd_line(int*, char*[]);

answered Feb 13, 2022 at 11:59

klutt

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1 Comment

hepl Over a year ago

yeah thanks. when i changed place of *, it worked. but now i have further problems:)

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