Converting contents of string array to int in java [duplicate]

Question

I am new to java programming. My question is this I have a String array but when I want to use the contents in a calculation I keep getting the error:

Type mismatch: cannot convert from String to int

My code is:

    public void process(String data) {
        int i, x, length,avg;
        String[] parts = data.split("\r");
        for (i = 0; i < data.length(); i++) {
            x = parts[i];
            avg = avg+x;
            length = length + i;
        }
        averageRate = avg / (length+1);
    }

Robert · Accepted Answer · 2022-02-20 21:24:29Z

4

Using Integer.parseInt() should solve it.

public void process(String data) {
    int length = 0, avg = 0; // These need initialization
    String[] parts = data.split("\\r");
    for (int i = 0; i < data.length(); i++) {
        int x = Integer.parseInt(parts[i]); // Change is here
        avg = avg + x;
        length = length + i;
    }
    averageRate = x / (length + 1);
}

edited Feb 20, 2022 at 21:24

Robert

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answered Feb 20, 2022 at 20:58

niklasenberg

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2 Comments

Ethan Fish Over a year ago

Once I add Integer.parseInt() a new error appears: Exception in thread "main" java.lang.NumberFormatException: For input string: "1.29\r1.31\r1.30\r1.29\r1.30\r1.30\r1.31\r1.27\r1.28\r1.27\r1.25\r1.29\r" at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:67) at java.base/java.lang.Integer.parseInt(Integer.java:668) at java.base/java.lang.Integer.parseInt(Integer.java:786) at ERDataProcessor.process(ERDataProcessor.java:21) at CW1_3.main(CW1_3.java:58)

niklasenberg Over a year ago

Then your String is not the proper format to be able to convert it to an Integer. Try formatting it first. Also, it looks to me that Double.parseDouble should be used, since the numbers in your String have decimals in them.

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