<?php $sizeh = '<script type="text/javascript">
document.write(viewportheight);</script>';
echo $sizeh;
echo gettype ($num);
$num = (int) $sizeh;
//$num = intval($sizeh);
echo gettype ($num);
echo $num;
?>
This results is:
1083 string integer 0
Why I am getting the value of zero while that zero should be 1083 ??
you're trying to change int value from $sizeh, not from $num. $sizeh is that your javascript code
Look here
<?php
$sizeh = '<script type="text/javascript">
document.write(viewportheight);</script>';
$num = "1083";
echo $sizeh;
echo gettype ($num)." ";
echo $num." ";
$num = (int) $num;
//$num = intval($sizeh);
echo gettype ($num)." ";
echo $num;
?>
You are mixing outputs from both JavaScript and PHP. 1083 is being written by JavaScript code. string, integer and 0 are being echoed by your PHP code.
<?php $sizeh = '<script type="text/javascript">
document.write(viewportheight);</script>';
$sizeh now is this ugly string. You will see 1083 in your browser because your browser run JS. But it will after php stop works
The problem is that you are looking at the browser window and not at the source code: $sizeh is a string, starting with <script type .... When you cast that string to an integer, the result is 0.
You cannot capture the output of javascript in php as the php is processed first, then sent to the browser after which the browser executes the javascript. To send a javascript value back to php you would need to post a form or use ajax.
$sizeh1083? Your PHP script cannot see the values of javascript like that.