imageMagick: Using Variable instead of Constant as Parameter in bash script

Question

I am using the following command sequence (which works pretty well)

convert $PIC -extent ${PIC_PX}x${PIC_PY}+0+0 \
  '(' +clone -alpha transparent -draw 'circle 1920,1080 1920,0' ')' \
  -compose copyopacity -composite circle.png

Now I want to substitute constants by variables

Var1=1920;
Var2=1080;
Var3=1920;
Var4=0

Can you help me with the right notation, please?

Thanks in advance

The semicolons in your variable assignments are superfluous. Also, always double-quote shell variables that you are expanding, i.e. convert "$PIC" ... and note that the shell reserves variables named in all uppercase letters for its own internal use. — Mark Setchell
– Mark Setchell, Commented Mar 6, 2022 at 21:09

fmw42 · Accepted Answer · 2022-03-06 20:26:15Z

1

In Imagemagick 6, that would be the following. But you need to change your single quotes on the -draw arguments to double quotes.

convert $PIC -extent ${PIC_PX}x${PIC_PY}+0+0 \
  '(' +clone -alpha transparent -draw "circle ${Var1},${Var2} ${Var3},0" ')' \
  -compose copyopacity -composite circle.png

answered Mar 6, 2022 at 20:26

fmw42

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1 Comment

Mark Setchell Over a year ago

You should also upvote it, btw.

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