How to call a function after an asynchronous for-loop?

Question

I have the following for-loop:

for await (const account of accountCursor) {
  const newAccount = handleAccount(account, migrationService);
  try {
    await migrationService.accountService.create(newAccount);
  } catch (error) {
    console.log('Unable to create account');
    throw Error(error)
  }
}

handleRelatedAccounts();  // call once the for-loop has completed

Once it has finished, I want to call another function. Since it is asynchronous, how can I call the function after the for-loop has finished, not during?

jsejcksn · Accepted Answer · 2022-03-18 17:16:34Z

1

Assuming you want to run the function whether or not an error is caught and re-thrown in your loop, you can just wrap the entire loop in a try...finally statement: below is an example. (If not, I'm not sure why you are re-throwing the caught error and what kind of behavior you expect.)

try {
  for await (const account of accountCursor) {
    const newAccount = handleAccount(account, migrationService);
    try {
      await migrationService.accountService.create(newAccount);
    } catch (error) {
      console.log('Unable to create account');
      throw Error(error)
    }
  }
}
finally {
  handleRelatedAccounts();  // call once the for-loop has completed
}

answered Mar 18, 2022 at 17:16

jsejcksn

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2 Comments

Jake Jackson Over a year ago

From one Jackson to another (I'm assuming that's what jcksn is supposed to mean), thank you. I completely forgot about finally{}.

jsejcksn Over a year ago

@JakeJackson It does :)

Thai Dang · Accepted Answer · 2022-03-18 17:32:29Z

0

You do not have to do anything. handleRelatedAccounts(); always run after the loop. await means it will wait until the premise is finished to do the next code. Because you throw Error(error), it will stop the execution when there is an exception, handleRelatedAccounts(); will be never hit in this case.

answered Mar 18, 2022 at 17:32

Thai Dang

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